Question

if (x) square +(1/x) square=27 then find the value of (x) cube+(1/x) cube​

Answer 1

Answer:

26$\sqrt{29}$ = x3 + 1/x3

Step-by-step explanation:

(x + 1/x)2 = x2 + 1/x2 + 2

(x + 1/x)2 = 27 + 2

x + 1/x = root (29)

(x + 1/x)3 =  x3 + 1/x3 + 3(x+1/x)

29$\sqrt{29\\}$ = x3 + 1/x3 + 3$\sqrt{29}$

29$\sqrt{29\\}$ - 3$\sqrt{29}$ = x3 + 1/x3

26$\sqrt{29}$ = x3 + 1/x3

Hope this helps:)