if x square + 1/x square = 7 find the value of x + 1/x , x > 0
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Answer:
x^2+(1/x^2)=7
x-(1/x)=??
square x-(1/x)
x^2-2+(1/x^2)
substitute
x^2+(1/x^2)=7
7-2=5
(x-[1/x])^2=5
take the square root of both sides
x-(1/x)=√5
Step-by-step explanation:
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