if X square + 1 x square equal 38 then find the value of x minus one upon x under the bracket
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6 would be the answer
x^2+(1/x^2) = 38
x^2 +(1/x^2) - 2 = 36
(x-1/x)^2 = 36
(x-1/x) = √36
x -1/x = 6
Remember (a-b)^2 = a^2 + b^2 -2ab
x^2+(1/x^2) = 38
x^2 +(1/x^2) - 2 = 36
(x-1/x)^2 = 36
(x-1/x) = √36
x -1/x = 6
Remember (a-b)^2 = a^2 + b^2 -2ab
ak67ak47:
9.
your class?
then whats the problem
see.....
(a-b)^2 = a^2 + b^2 -2ab
ohh....... thanks you used identity
then (x-1/x)^2 = x^2+1/x^2 -2(X×1/X)
understood?
yeah!
u r from?
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49
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