Question

If X square + 1 x square is equal to 17 by 4 then find the value of x + 1 by x x cube minus 1 x cube and x cube + 1 by x cube

Answer 1

Answer:

=1/√17×X/2

Step-by-step explanation:

If,

X^2+1x^2=17/4

4x^2= 17X^2

x^2=17X^2/4

√x^2=√17X^2/4

x=√17 ×X/2

then,

=[x+1/x(x^3)]- [x^3+1/x^3]

= [(x+1)/x(x^3)]-[(x^2)+(x+1)/x^3]

=[1/(x^3)]-(1/1)

= [1/(√17×X/2)]-(1/1)

= [1/(√17×X/2)]

=1/√17×X/2