if x square +1/xsquare=3 find the value of x +1/x
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- x^2+1\x^2=3
- x^2+1=3x^2
- 3x^2-x^2+1=0
- 2x^2+1=0
- x^2= -1\2
x=1\√2
:x+1\x
- [(1\√2)+1]÷(1\√2)
- [(1+√2)÷√2]× √2
=[1+√2 ]
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Answer:
Adding two on both sides we get,
=
As (a+b)² = a² + b² + 2ab
so
Now,
√5
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