If x square 3+ ax square 2-bx+10 is divisible by x square 2-3x+2, find the values of a and b
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Step-by-step explanation:
x³+ax²-bx+10---eq 1; x²-3x+2---- eq 2
x²-3x+2=(x-1)(x-2)
calculate f(1)=0
for equation 1....
1+a-b+10=0
for equation 2....
a-b=-11-----eq3
f(2)=0
2³+2²a-2b+10=0
8+4a-2b+10=0
8+4a-2b=-10
4a-2b =-18
2a-b=-9----eq 4
sub 3 from 4
a-2a-b+b=11+9
-a=-2
a=2
from equations
a-b=-11
2-b=-11
b=13
therefore...a=2, b=13
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