Question

if x square - 4 =(x-m)(x-l) then find the value of L + M and l m​

Answer 1

Step-by-step explanation:

x² -4 = (x-m) (x-l)

= (x+2) (x-2)

Answer 2

Answer:

${x }^{2} - 4 = (x - l)(x - m) \\ {x}^{2} - {2}^{2} = (x - l)(x - m) \\ (x + 2)(x - 2) = (x - l)(x - m)$

Then ,

$(x + 2) = (x - l) \\ l = - 2$

On the other hand ,

$(x - 2) = (x - m) \\ - 2 = - m \\ m = 2$So ,

$l + m = - 2 + 2 \\ = 0 \\ \\ \\ \\lm = - 2 \times 2 \\ = - 4$