Question

If x square by a square +y square by b square =1 . Prove that dy by dx =-b square x by a square y

Answer 1

here is your answer!.........

Answer 2

Answer: To prove : $dy/dx=-b^{2}x/a^{2}y$

Step-by-step explanation:

To prove:

$dy/dx=-b^{2}x/a^{2}y$

Given:

$x^{2}/a^{2}+y^{2}/b^{2}=1$

Differentiating the given equation on both sides with respect to x:

$2x/a^{2}+2y/b^{2}\times dy/dx=0\\\\2y/b^{2}\times dy/dx=-2x/a^{2}\\\\dy/dx=-2x/a^{2}\times\ b^{2}/2y=-b^{2}x/a^{2}y$

Hence proved.