if x square root +y square root =89and xy =40, then find the value of x cube roots +y cube roots
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Given that :
x² + y² = 89 .....(i)
and
xy = 40 .....(ii)
From (i), we get :
(x + y)² - 2xy = 89
=> (x + y)² - (2 × 40) = 89, by (ii)
=> (x + y)² - 80 = 89
=> (x + y)² = 169 = 13²
So, x + y = ± 13
Taking the positive value, we write :
x + y = 13
So, x³ + y³
= (x + y)(x² + y² - xy)
= 13 × (89 - 40)
= 13 × 49
= 637.
Taking the negative value, we write :
x + y = -13
So, x³ + y³
= (x + y)(x² + y² - xy)
= (-13) × (89 - 40)
= - 13 × 49
= - 637
♧♧HOPE THIS HELPS YOU♧♧
Given that :
x² + y² = 89 .....(i)
and
xy = 40 .....(ii)
From (i), we get :
(x + y)² - 2xy = 89
=> (x + y)² - (2 × 40) = 89, by (ii)
=> (x + y)² - 80 = 89
=> (x + y)² = 169 = 13²
So, x + y = ± 13
Taking the positive value, we write :
x + y = 13
So, x³ + y³
= (x + y)(x² + y² - xy)
= 13 × (89 - 40)
= 13 × 49
= 637.
Taking the negative value, we write :
x + y = -13
So, x³ + y³
= (x + y)(x² + y² - xy)
= (-13) × (89 - 40)
= - 13 × 49
= - 637
♧♧HOPE THIS HELPS YOU♧♧
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