If x square+y square=13 and xy=6
Find the value of:
x+y
x-y
x power 4+ y power 4
Answers
Answered by
30
(x+y)²=x²+y²+2xy
(x+y)²=13+2(6) = 13+12 = 25
(x+y) =√25 =5
(x-y)²=x²+y²-2xy
(x-y)²=13-2(6) =13-12=1
(x-y) =√1=1
x⁴+y⁴=(x²)²+(y²)²
= (x²)²+(y²)²+2x²y²-2x²y²
= [x²+y²]²-2x²y² = (13)²-(√2xy)²
x⁴+y⁴ = 169-(6√2)² = 169-72 = 97
hope this helps
(x+y)²=13+2(6) = 13+12 = 25
(x+y) =√25 =5
(x-y)²=x²+y²-2xy
(x-y)²=13-2(6) =13-12=1
(x-y) =√1=1
x⁴+y⁴=(x²)²+(y²)²
= (x²)²+(y²)²+2x²y²-2x²y²
= [x²+y²]²-2x²y² = (13)²-(√2xy)²
x⁴+y⁴ = 169-(6√2)² = 169-72 = 97
hope this helps
Answered by
2
Answer:
I don't know sorry, the above answer is correct
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