Question

If x square + y square = 14 xy, Then prove that 2 log (x+y) = 4 log2 +logx + logy​

Answer 1

Answer:

x^2 + y^2= 14xy

x^2 + y^2 +2xy = 14xy+2xy

(x+y)^2=16xy

Applying log on both sides

log(x+y)^2=log16xy

2log(x+y)= log16 + logx + logy

2log(x+y) = log2^4+ logx + logy

2log(x+y) =4log2 + logx + logy