Question

If x square + y square=25xy then prove 2log(x+y) =3log3+ logx +logy ​

Answer 1

Answer:

Step-by-step explanation:

$x^{2} + y^{2} = 25xy$

Adding 2xy to both the sides we get :

$x^{2} +y^{2} + 2xy = 27xy$

Factorizing the LHS

$(x+y)^{2} = 27xy$                 - (i)

Assuming that you know the log formulas

2log(x+y) = 3log(3) + log(x) + log(y)

2log(x+y) = log(27) + log(xy)

2log(x+y) = log(27xy)

$log (x+y)^{2} = log (27xy)$

log (27xy) = log (27xy)     (by (i))

Hence Proved.

Hope this helped you.