if x square +y square =25xy then prove that 2log (x+y)=3log cube+logx+logy
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49
x^2 + y^2 = 25xy
2log (x+y) = 3log 3 + logx + log y
log (x+y)^2 = 3log 3 + logx + log y
log (x^2 +y^2 + 2xy ) = 3log 3 + logx + log y
now, substitute the value for x^2 + y^2
log (25xy + 2xy) = 3log 3 + logx + log y
log 27 xy = 3log 3 + logx + log y
log 27 + log x + log y = 3log 3 + logx + log y
log 3^3 + log x + log y= 3log 3 + logx + log y
3 log 3 +log x + log y = 3log 3 + logx + log y
2log (x+y) = 3log 3 + logx + log y
log (x+y)^2 = 3log 3 + logx + log y
log (x^2 +y^2 + 2xy ) = 3log 3 + logx + log y
now, substitute the value for x^2 + y^2
log (25xy + 2xy) = 3log 3 + logx + log y
log 27 xy = 3log 3 + logx + log y
log 27 + log x + log y = 3log 3 + logx + log y
log 3^3 + log x + log y= 3log 3 + logx + log y
3 log 3 +log x + log y = 3log 3 + logx + log y
Answered by
40
hope it helps you ..........
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