if x square + y square = 6 xy then prove that 2log( x+y ) = logx+logy+3log2
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Step-by-step explanation:
x^2+y^2=6xy
x^2+y^2+2xy=6xy+2xy
(x+y)^2=8xy
log(x+y)^2=log(8xy)
2log(x+y)=log8+logx+logy since logx^ n= n logx
log(ab)=loga+logb)
2log(x+y)= =log2^3+logx+logy
2log(x+y)= =3log2+logx+logy
2log( x+y ) = logx+logy+3log2
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