Question

if x square + y square = 65 , xy = 28 find [x-y]the whole square

Answer 1

Given:

$x^{2} + y^2 = 65$

xy = 28

To find:

$(x-y)^2$

Solution:

The given equations are

$x^{2} + y^2 = 65$            ( 1 )

xy = 28                   (2)

Now, we will put these values in $(x-y)^{2}$

$(x-y)^{2}$ = $x^2 + y^2 -2xy$

putting values from equation (1) and (2)

$(x-y)^{2}$ = 65 - 2(28)

$(x-y)^{2}$ = 9

Therefore, the value of $(x-y)^{2}$ will be 9.