Question

if X square+ y square = 7xy... prove that log x + y =log 3+1/2 (log x+log y)


please help me!​

Answer 1

Answer:

if the the answer of the first problem is 7 x y so you take the log of X + y it is wrong take X + x and ad with 7 hope it helped you bro

Answer 2

Answer:

Given x² + y² = 7xy

=> x² + y² + 2xy = 7xy + 2xy

=> (x+y)² = 9xy

=> log(x+y)² = log (3²xy)

=> 2log(x+y) = log3² + logx + logy

log a^{m} = m logaloga

m

=mloga

log (mn) = log m + log nlog(mn)=logm+logn

=> 2log(x+y)= 2log3 + log x + log y

/* dividing both sides by 2, we get

log(x+y) =log3 +1/2 (logx+logy)