if x square + y square is equal to 6 x y prove that 2 log (X + Y) is equal to log x + Y + 3 log 2
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given that
x^2+y^2=6xy
so 2log(x+y)=log(x+y)^2=log(x^2+y^2+2xy)
=log(6xy+2xy)
= log(8xy)
=log(8)+log(x)+log(y)
=log(2)^3+log(x)+log(y)
=3log2+log(x)+log(y)
x^2+y^2=6xy
so 2log(x+y)=log(x+y)^2=log(x^2+y^2+2xy)
=log(6xy+2xy)
= log(8xy)
=log(8)+log(x)+log(y)
=log(2)^3+log(x)+log(y)
=3log2+log(x)+log(y)
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