If X square + y square + z square equals to 40 and xy + y z plus ZX equals to 12 then find the value of x + y + z
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x² +y² +z² = 40
xy + yz +xz =12
x +y+ z= ?
( x+ y +z )² = x² + y² + z² +2xy +2yz +2xz
( x +y +z)²= x² + y² +z ²+2xy +2yz +2xz
(x+y+ z)²= 40 + 24
x+ y+ z=root(64)
x+y+z=8
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Answer:
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