Math, asked by vishaln7595, 1 year ago

if x squared minus y squared equal to 18 and x minus y equal to 3 then find the value of 16x squared y squared

Answers

Answered by Anonymous
7

Answer:

Given;

x^2 - y^2 = 18

x - y = 3

.To find;

16(x^2)(y^2) = ?

Solution;

We have,

=> x^2 - y^2 = 18

=> (x-y)(x+y) = 18 -----(1)

Also,

x - y = 3 ------(2)

Now,

Putting the value of (x-y) = 3 in eq-(1)

We get,

=> (x-y)(x+y) = 18

=> 3(x+y) = 18

=> x + y = 18/3

=> x + y = 6 -------(3)

Now,

Adding eq-(2) and (3);

We get;

=> x - y + x + y = 3 + 6

=> 2x = 9

=> x = 9/2

Now,

Putting x = 9/2 in eq-(2) ,

We get;

=> x - y = 3

=> 9/2 - y = 3

=> y = 9/2 - 3

=> y = (9-6)/2

=> y = 3/2

Thus,

16(x^2)(y^2) = 16{(9/2)^2}•{(3/2)^2}

= 16 (81/4)•(9/4)

= 16 (729/16)

= 729

Thus, the required value of 16(x^2)(y^2)

is: 729

Answered by Anonymous
8

Answer:

 {x}^{2}  -  {y}^{2}  = 18 \\ x - y = 3 \\ 16 {x}^{2} {y}^{2} = ?  \\ (x + y)(x - y) = 18 \\ (x + y)3 = 18 \\ x + y = 6 \\  \\ solving \: x + y = 6 \: and \: x - y = 3 \\  \\ we \: get \: x = 4.5  \: and \: y = 1.5 \\  \\ 16 {x}^{2}  {y}^{2}\:  = 16 \times  {4.5}^{2}  \times  {1.5}^{2} \\ 16 {x}^{2} {y}^{2}= 729

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