if x squared minus y squared equal to 18 and x minus y equal to 3 then find the value of 16x squared y squared
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7
Answer:
Given;
x^2 - y^2 = 18
x - y = 3
.To find;
16(x^2)(y^2) = ?
Solution;
We have,
=> x^2 - y^2 = 18
=> (x-y)(x+y) = 18 -----(1)
Also,
x - y = 3 ------(2)
Now,
Putting the value of (x-y) = 3 in eq-(1)
We get,
=> (x-y)(x+y) = 18
=> 3(x+y) = 18
=> x + y = 18/3
=> x + y = 6 -------(3)
Now,
Adding eq-(2) and (3);
We get;
=> x - y + x + y = 3 + 6
=> 2x = 9
=> x = 9/2
Now,
Putting x = 9/2 in eq-(2) ,
We get;
=> x - y = 3
=> 9/2 - y = 3
=> y = 9/2 - 3
=> y = (9-6)/2
=> y = 3/2
Thus,
16(x^2)(y^2) = 16{(9/2)^2}•{(3/2)^2}
= 16 (81/4)•(9/4)
= 16 (729/16)
= 729
Thus, the required value of 16(x^2)(y^2)
is: 729
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Answer:
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