if x= t+1/t-1, y= t-1/t+1 then show that y² +dy/dx=0
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Given, x = sin^-1t or sin x = t and y = log(1 - t^2) = log(1 - sin^2x) = log(cos^2x) Hence, y = 2log(cosx) Therefore, dydx = -2sinxcosx = - 2tan x d^2ydx^2
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