if x=t^2-6t+4 then find 1)average speed in 5 second 2) average velocity in 5 second
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- speed = distance/ time
distance which is x when we put t = 5,
x = -1 or 1 because distance can not be negative
now avg speed = 1/time = 0.2 m/s
2. avg velocity ?
velocity is dx/dt = 2t-6
now put t = 5
therefore AVG VELOCITY = 4 m/s
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