Question

if x= t log t and y= log t/t, find dy/dx for t=1.​

Answer 1

Step-by-step explanation:

I hope you would understand this afterwards please make it brainliest

Answer 2

Answer:

Answer is 1.

Step-by-step explanation:

x = t, y = log⁡〖t 〗/t    

dx/dt = 1

dy/dt = (t.$\frac{1}{t}$  -log⁡〖t .1〗)/t^2 =(1-log⁡t)/t^2  

dy/dx =(1-log⁡t)/t^2    

At t = 1

dy/dx  =(1-log⁡1)/(1)^2 =(1 -0)/1=1.