Question

If x=(t-sint),y=b(1-cost) find d2y/dx2 at t=pi/2

Answer 1

Answer:

0

Step-by-step explanation:

y=b-bcost

dy/dt= -b(-sint)= bsint

d2y/dt2= bcost

x=t-sint

dx/dt=1-cost

d2x/dt2=0-(-sint)=sint

now;

d2y/dt2 / d2x/dt2= d2y/dx2= bcost/sint

at t=π/2

d2y/dx2=bcosπ/2 / sinπ/2

             =b×0 / 1

             =0