If x Tan^210°+4Cos^150°=9 then x=
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x tan (270-60) + 4cos (90+60)=9
x tan (3×90-60)+ 4 cos (90+60)=9
xcot(60) + 4[-sin(60)] =9
x/√3 + 4(-√3/2) =9
x/√3 + (-2√3) =9
x/√3 - 2√3 =9
(x - 2×√3×√3)/√3 = 9
x - 6 =9√3
x = 9√3 + 6
may be, this can be your answer..............
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