Math, asked by sriharshithbatthula, 1 month ago

If x=tanθ+cotθ, y=secθ−cosθx=tanθ+cotθ, y=secθ−cosθ, then (x4y2)13−(x2y4)13(x4y2)13−(x2y4)13 is equal to

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Answered by sujathag270

0

Answer:

can you please rewrite the question please. because the question is wrong.

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