if x tan²60+cosec41=cot45+sec49,then find the value of x.
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Answer:
1/3
Step-by-step explanation:
xtan^2 60+cosec 41=cot 45 + sec 49
x(√3)^2 + cosec 41= 1 + sec 49
3x = 1 + 1/cos 49 - 1/ sin 41
3x= 1+ 1/cos 49 - 1/ cos 49 [as sin(90- theeta)= cos theeta]
3x= 1
x=1/3.
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