Question

If x=
$1 + \sqrt{2}$
find the value of
${x}^{2} \times 1 \div {x}^{2}$
​

Answer 1

ANSWER :-

if

$\frac{ {x}^{2} \times 1}{ {x}^{2} } ...then \: the \: value \: comes \: out \: to \: be \: 1$

therefore the value can be equal to '1'.

THNKS!

Answer 2

Answer:

1

Step-by-step explanation:

As we have given in the question we need to solve for $x^{2}\times\dfrac{1}{x^{2} }$, Where e have given that

$x=1+\sqrt{2}$  but as we see the equation it becomes 1 itself we don't Need to put the value of x in the equation.

As we know by mathematical property $\dfrac{x^{2} }{x^{2} }=1$

Therefore the final answer to this question would be 1 as all the variables Will cancel itself and tends to 1