Question

if x=
$2 + \sqrt{2 + \sqrt{2 + \sqrt{2....... ...} } }$

then value of x=?
​

Answer 1

Answer:

x = 4 or 1

Step-by-step explanation:

x = 2 + $\sqrt{x}$2 + $\sqrt{x}$2 + ................................................

⇒ x = 2 + √x

⇒ √x = 2-x

⇒ x = x² + 4 - 4x

⇒ x² - 5x +4

     x² - x - 4x + 4

      ⇒ x = 4 or 1

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