Math, asked by ritu7997, 1 year ago

If x =
3 +  \sqrt{8}
Find
 {x}^{2} +  \frac{1}{ {x}^{2} }

Answers

Answered by Anonymous
2

Here is the answer...!!!

Refer to the attachment

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Answered by Jbhandari
0

Answer:

X ka square krnaa h a+b ka square vala FORMULA

(3+√8) SQUARE

TO AYEGA 17+6√8

x^2+1/x^2+2x*1/x=17+6√8-2

answer is 15+6√8


Jbhandari: sorry galat h meraa
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