Question

if x=
$\frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$
and
$y = \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$
find
${x}^{2} + {y}^{2}$

​

Answer 1

Answer:

x=(√3+√2)/(√3-√2)

y=(√3-√2)/(√3+√2)

x.y=(√3+√2)/(√3-√2).(√3-√2) /(√3+√2)=1

x+y=(√3+√2)/(√3-√2)+(√3-√2)/(√3+√2)

={(√3+√2)^2+(√3-√2)^2}/(√3+√2)(√3-√2)

=(3+2+2√6+3+2-2√6)/(√3^2-√2^2)

=10/(3-2)

=10/1

=10

x^2+y^2

=(x+y)^2-2xy

=(10)^2-2×1

=100-2

=98

Answer 2

Answer:

98

Step-by-step explanation:

hope it helps....

have a nice day ahead....