Question

If x =
$\sqrt{6} + \sqrt{5}$
then what is value of x2 + 1/x2​

Answer 1

Answer:

x = √6 + √5

1/x = 1/(√6+√5)

rationalise the denominator

1/x = √6-√5

we know

(x+ 1/x)² = x² + 1/x² + 2x.1/x

(√6 + √5 + √6 - √5)² = x² + 1/x² + 2

(√6)² = x² + 1/x² + 2

x² + 1/x² = 6 - 2

x² + 1/x² = 4

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Answer 2

Step-by-step explanation:

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