If x+then factor of x²3+3x²2+3x+1
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Step-by-step explanation:
(a) x2−3x+2=x2−2x−x+2=x(x−2)+1(x−2)=(x+1)(x−2)
(b) Since x2−3x+k can be written as the product of two first degree polynomials,
b2−4ac=0
(3)2−4(1)(k)=0⇒9−4k=0
k=9/4
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