if x to the power 2 + y to the power 2=6xy.now prove that 2log(x+y)=logx+logy+3log2
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x² + y² = 6 x y
x² + y² + 2 x y = 8 x y
=> (x+y)² = 8 x y
=> Log (x+y)² = Log (8 x y)
=> 2 Log (x+y) = Log 8 + log x + log y
= Log 2^3 + log x + Log y
= 3 log 2 + log x + log y
x² + y² + 2 x y = 8 x y
=> (x+y)² = 8 x y
=> Log (x+y)² = Log (8 x y)
=> 2 Log (x+y) = Log 8 + log x + log y
= Log 2^3 + log x + Log y
= 3 log 2 + log x + log y
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