Question

if x to the power one by three plus y to the power one by three plus z to the power one by three is equal to zero then x plus y plus z whole to the power three is equal to how much?

Answer 1

Heya......!!!

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Given in the question :- x^⅓ + y^⅓ + z^⅓ = 0 

We have to take out the value of => ( x + y+ z )^3

→ Let x = p
→ y = q
→ z = r

Then => p + q + r = 0

➡ Now the cube of p,q and r is equal to

➡ p³ + q³ + r³ = 3pqr

Putting the values of p , q and r we get :

➡ (x^⅓)³ + (y^⅓)³ + (z^⅓)³ = 3(x^⅓)(y^⅓)(z^⅓) 

➡ x + y + z = 3(xyz)^1/3

➡ Cube both the sides ,,,, we get :-


♦ ➡ (x + y + z)³ = 27xyz


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Hope It Helps You ^_^