Math, asked by mozu33, 1 year ago

if x=under route3-route2\route3+route2,y=route3+route2\route3-route2,find the value of xsquar2+y squar2+xy.
PLEASE ANSWER FAST

Answers

Answered by aroravinita36

2

Answer:

the value of x square + y square +xy =99

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mozu33: thank uh so much

aroravinita36: is the answer correct??

mozu33: may be

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