Physics, asked by RajThakur153, 1 year ago

If x v and a denote the displacement velocity and acceleration of a particle executing simple harmonic motion of time period t then which doesnt change with time

Answers

Answered by gadakhsanket
15

Hey dear,

You have posted incomplete question. I've added complete question as image.


◆ Answer-

(ii) aT/x


◆ Explanation-

We have to solve this question by try and error method. You can try all the options, but here I'll explain only right answer.


Independently x, v & a all are variable.

aT/x = (-xω^2)T/x

aT/x = -Tω^2

aT/x = -T(2π/T)^2

aT/x = -4π^2 / T


As time period is constant, aT/x must be constant.


Hope this helps...








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Answered by Anonymous
1

Answer:

Hey dear,

You have posted incomplete question. I've added complete question as image.

◆ Answer-

(ii) aT/x

◆ Explanation-

We have to solve this question by try and error method. You can try all the options, but here I'll explain only right answer.

Independently x, v & a all are variable.

aT/x = (-xω^2)T/x

aT/x = -Tω^2

aT/x = -T(2π/T)^2

aT/x = -4π^2 / T

As time period is constant, aT/x must be constant.

Hope this helps...

Explanation:

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