If x v and a denote the displacement velocity and acceleration of a particle executing simple harmonic motion of time period t then which doesnt change with time
Answers
Hey dear,
You have posted incomplete question. I've added complete question as image.
◆ Answer-
(ii) aT/x
◆ Explanation-
We have to solve this question by try and error method. You can try all the options, but here I'll explain only right answer.
Independently x, v & a all are variable.
aT/x = (-xω^2)T/x
aT/x = -Tω^2
aT/x = -T(2π/T)^2
aT/x = -4π^2 / T
As time period is constant, aT/x must be constant.
Hope this helps...
Answer:
Hey dear,
You have posted incomplete question. I've added complete question as image.
◆ Answer-
(ii) aT/x
◆ Explanation-
We have to solve this question by try and error method. You can try all the options, but here I'll explain only right answer.
Independently x, v & a all are variable.
aT/x = (-xω^2)T/x
aT/x = -Tω^2
aT/x = -T(2π/T)^2
aT/x = -4π^2 / T
As time period is constant, aT/x must be constant.
Hope this helps...
Explanation: