if x varies as y² and y=z when x=6. Find out the relation between x & y
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Answer:
x varies inversely as square of y, so we can say x=y2n.
Given: y=2 and x=1
⇒1=(2)2n
⇒(2)2=n
⇒n=4
So, if y=6 we have, x=(y)2n
⇒x=(6)24 = 364 = 91
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I hope it will be help you
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