Question

if x varies directly as y and inversely as z and if x=a and y=b and z=c find x when y= b^2 and z=c^2

Answer 1

Answer:

x varies directly with z, so: X ~ Y or, X=KY

and similarly X=M/Z.

as given values if x, y, z we get K= a/b and M= ac.

so, X= KY= a/b*b^2=ab

or, x=a/c

Answer 2

Answer:

We have $x=ab$ or $x=a/c$.

Step-by-step explanation:

It is given that:

$x$ varies directly as $y$

$x$ varies inversely as $z$

We have

$x=a$

$y=b$

$z=c$

We need to determine $x$ when $y= b^2$ and $z=c^2$

Relation between $x,y$ is

$x=ky$

Relation between $x=m/z$

Hence, $k=a/b$ and $m=ac$

So, $x=ky=\frac{a}{b}*b^{2}$

$x=ab$

and $x=a/c$

#SPJ2