Math, asked by priya9468, 3 months ago

If x varies directly as y and inversely as z and x = 12 when y = 9 and z = 16, find y when x = 9 and z = 24.​

Answers

Answered by svanshjeet
3

Step-by-step explanation:

If x varies directly as y and inversely as z and x = 12 when y = 9 and z = 16, find y when x = 9 and z = 24.

I think answer is already given in question

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Answered by pulakmath007
3

The value of y = 81/8

Given :

  • x varies directly as y and inversely as z
  • x = 12 when y = 9 and z = 16

To find :

The value of y when x = 9 and z = 24.

Solution :

Step 1 of 2 :

Find constant of variation

Here it is given that x varies directly as y and inversely as z

Thus we have

\displaystyle \sf{ \implies x \propto \: y \: and \:  \: x \propto \:  \frac{ 1 }{z} }

\displaystyle \sf{ \implies  x \propto \:  \frac{ y }{z} }

\displaystyle \sf{ \implies  x  =  \:  \frac{k y }{z} }

x = 12 when y = 9 and z = 16

This gives

\displaystyle \sf{ \implies  12  =  \:  \frac{9k }{16} }

\displaystyle \sf{ \implies  k =  \frac{12 \times 16}{9} }

Step 2 of 2 :

Find the value of y

\displaystyle \sf{   x  =  \:  \frac{k y }{z} }

\displaystyle \sf{  \implies  9  =  \:  \frac{ky}{24} }

\displaystyle \sf{  \implies  9  =  \:  \frac{y}{24} } \times  \frac{12 \times 16}{9}

\displaystyle \sf{  \implies  9  =  \:  \frac{8y}{9} }

\displaystyle \sf{  \implies  y  =  \frac{81}{8} }

The value of y = 81/8

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