If x varies directly with 3y + 5 and y = 5/3
when x = 10, then what is the value of y when x =36
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Answered by
24
x Varies directly with 3y+5
i.e., x=K(3y+5)
If y= 3/5
when x=10
⟹10=K(3×3/5 +5)
⟹10=K( 9/5+5)
⟹10=K× 5/34
⟹K=10× 5/35
= 25/17
∴x= 17 /25 (3y+5)
When x=35 then,
35= 17 /25 (3y+5)
∴y= 15 /94
Answered by
0
∴y= 15 /94
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