if x varies inversely as the cube of y when the y= 5 and the value of x= 81. what will be the value of y when X=3
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y×1/x
to make the variation sign to equal to we introduced a constant k.
y=k/x³
k=y×x³ and when y=5,x=81
81³=9
k=5×9=45
y=k/x [y=45/x] this is the relationship between y and x.x=3
x=45/3=15.
hope it will help us.....
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if x varies inversely as the cube of y when the y= 5 and the value of x= 81. what will be the value of y when X=3
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