Question

If x varies inversely as y^2 and x =3 when y =4 , find x when y=2. Please Give Answer​

Answer 1

Answer:

Answers is X = 12

I Hope u understand

My friend

Answer 2

$\large\sf\underline{↬\:Given}$

$\sf\:x∝\frac{1}{y^{2}}\:$

$\sf\:x=\frac{k}{y^{2}}\:$ ------(i)

• where k = constant of proportionality

$\large\sf\underline{↬\:Solution}$

$\sf\:when\:x=3\:and\:y=4$

$\sf➪\:x=\frac{k}{y^{2}}\:$

$\sf➪\:3=\frac{k}{4^{2}}\:$

$\sf➪\:3=\frac{k}{16}\:$

$\sf➪\:3 \times 16=k\:$

$\sf➪\:k=48\:$

$\sf\:Now\:when\:y=2\:we\:need\:to\:find\:x$

$\sf\:substituiting\:the\:value\:of\:k\:and\:y\:in\:(i)$

$\sf\:x=\frac{k}{y^{2}}\:$ ------(i)

$\sf➪\:x=\frac{48}{2^{2}}\:$

$\sf➪\:x=\frac{48}{4}\:$

$\sf➪\:x=12\:$

$\large\fbox\red{✰\: So\: x = 12}$

Thnku ❣