Math, asked by chandanrider2002, 6 months ago

If x varies inversely as y and x = 12 when y = 33, find x when y = 11.
(Hint: answer is x=36)
please tell me in process
please tell me the answer

Answers

Answered by pandagaming0276
0

Answer:

2 { \sqrt[ {7x {93 \frac{63 - .69 \div 2 >  + x \frac{5 {?}^{2} }{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?}  \times \frac{?}{?} }{?} }^{?} }^{2} ]{?} }^{2}  < .4 = 366 { { \frac{ \sqrt{ \sqrt{ \sqrt{694 \frac{ \frac{ \frac{ \frac{3 {(((((((33 =  \\ 55}^{?} }{?} }{?} }{?} }{?} } } } }{?} }^{2} }^{?}

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