Math, asked by agrgeetika1611, 5 months ago

If x varies inversely as y3 - 1 and is equal to 3 when
y = 2, find x when y = 4.
(b) 1/3
(d) 1
(a) 1/4
(c) 1/9​

Answers

Answered by aniketms421
3

Answer:

1/3

Step-by-step explanation:

as x is inversely proportional to y

y³-1 = k/x

when y is 2

7 = k/3

k=21

now , take y as 4

63= 21/x

x=1/3

Answered by rani78956
0

We know xy

x=ky

Where k is a constant

Given: y^3-1\frac{1}{x}

y^3-1=\frac{k}{x}

y^3-1=\frac{k}{3}

Here y=2

(2)^3-1=\frac{k}{3}

7=\frac{k}{3}

k=21

Now,

y^3-1=\frac{k}{x}

(4)^3-1=\frac{21}{x}

63=\frac{21}{x}

x=\frac{21}{x}

x=\frac{21}{63}

x=\frac{1}{3}

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