if x varies inversly as y^2-1 and is equal to 24 when y=10 , find x when y=5
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Since they vary inversely,
x(y^2-1) is constant.... = k
Given,
when y =10, x=24
So, k = 24(99)
Now, when y is 5
Then,
x(24) = 24*99
Hence, x is 99
x(y^2-1) is constant.... = k
Given,
when y =10, x=24
So, k = 24(99)
Now, when y is 5
Then,
x(24) = 24*99
Hence, x is 99
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