If x vary y inversrly and x=3 when y =8 find y when x=4 ?
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The statement is expressed as y∝1x
inverse means 1variable
To convert to an equation introduce k, the constant of variation.
y=k×1x
⇒y=kx
To find k use the given condition that y = 8 when x = 4
8=k4⇒k=4×8=32
⇒ equation is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣22y=32x22∣∣∣−−−−−−−−−−−−
x=16→y=3216
⇒y=2 when x=16
inverse means 1variable
To convert to an equation introduce k, the constant of variation.
y=k×1x
⇒y=kx
To find k use the given condition that y = 8 when x = 4
8=k4⇒k=4×8=32
⇒ equation is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣∣22y=32x22∣∣∣−−−−−−−−−−−−
x=16→y=3216
⇒y=2 when x=16
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