Question

If x ∈ W, then the solution set of (3x/5) - (2x-1)/3 > 1

Answer 1

Step-by-step explanation:

We have,

$\frac{3x}{5} - \frac{2x - 1}{3} > 1$

$= > \frac{9x - 10x + 5}{15} > 1$

$= > \frac{ - x + 5}{15} - 1 > 0$

$= > \frac{ - x + 5 - 15}{15} > 0$

$= > - x - 10 > 0$

$= > x + 10 < 0$

Since,

$x \in \: w$

so, no solution is possible

$= > x \in \phi$