Question

If x ∊ W, then the solution set of the inequation 3x+11 ≥ x +8 is1.{-2,-1,0,1,2,……..}2.{-1,0,1,2,………}3.{0,1,2,3,……….}4.{4,3}​

Answer 1

Answer:

2x ≥ 10. ⇒ 2x/2 ≥ 10/2 (Divide both sides by 2). ⇒ x ≥ 5. Replacement set = {0, 1, 2, 3, 4, 5, 6, ...} Therefore, solution set = {5, 6, 7, 8, 9, ...} or, S = {x : x ∈ W, x ...

Step-by-step explanation:

math

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

If x ∈ W , then the solution set of the inequation

3x + 11 ≥ x + 8 is

1. {-2,-1,0,1,2,....}

2. {-1,0,1,2,….}

3. {0,1,2,3,….}

4. {4,3}

EVALUATION

Here the given inequality is

3x + 11 ≥ x + 8

We simplify it as below

$\sf{3x + 11 \geqslant x + 8}$

$\sf{ \implies \: 3x - x \geqslant 8 - 11}$

$\sf{ \implies \: 2x \geqslant - 3}$

$\sf{ \implies \: x \geqslant - 1.5}$

Since x ∈ W

So the required solution set

= S = {0,1,2,3,….}

FINAL ANSWER

Hence the correct option is 3. { 0,1,2,3,….}

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