Question

if x+x^-1=11 evaluate the value of x^2+x^2
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Answer 1

Answer:

$x + \frac{1}{x} = 11$

$(x + \frac{1}{x})^{2} = 121$

${x}^{2} + \frac{1}{x^{2} } + 2 \frac{x}{x} = 121$

(x/x cancelled)

${x}^{2} + \frac{1}{ {x}^{2} } = 121 - 2 = 119$

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Answer 2

Answer:

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