Question

if x - ( x-1)/3 = ( x +1) then the value of x is​

Answer 1

$\large \bf \: x - \frac{(x - 1)}{3} = (x + 1) \\ \\ \large \bf \frac{x}{1} - \frac{(x - 1)}{3} = (x + 1) \\ \\ \large \bf \frac{x \times 3}{1 \times 3} - \frac{(x - 1)}{3} = (x + 1) \\ \\ \large \bf \frac{3x}{3} - \frac{(x - 1)}{3} = (x + 1) \\ \\ \large \bf \frac{3x - (x - 1)}{3} = (x + 1) \\ \\ \large \bf \frac{3x - x + 1}{3} = (x + 1) \\ \\ \large \bf \frac{2x + 1}{3} = (x + 1) \\ \\ \large \bf (2x + 1) = 3 \times (x + 1) \\ \\ \large \bf 2x + 1 = 3x + 3 \\ \\ \large \bf 2x - 3x = 3 - 1 \\ \\ \large \bf ( - 1)x = 2 \\ \\ \large \bf x = \frac{2}{ - 1} \\ \\ \underline{\underline{\large \bf x = ( - 2)}}$

$\\ \\ \bf \: Hope~~this~~helps~~you~!$

Answer 2

Step-by-step explanation:

( a - b ) ( c + d ) - ( a + b ) ( c - d ) + 2 ( ac - bd )

( a - b ) ( c + d )

= a ( c + d ) - b ( c + d )

= ac + ad - bc - bd

( a + b ) ( c - d )

= a ( c - d ) + b ( c - d )

= ac - ad + bc - bd

2 ( ac - bd ) = 2ac - 2bd

( a - b ) ( c + d ) - ( a + b ) ( c - d ) + 2 ( ac - bd )

= ac + ad - bc - bd - ( ac - ad + bc - bd )

+ 2ac - 2bd

= ac + ad - bc - bd - ac + ad - bc + bd

+ 2ac - 2bd

= ac - ac + 2ac + ad + ad - bc - bc + bd - bd - 2bd

= 0 + 2ac + 2ad - 2bc + 0 - 2bd

= 2ac + 2ad - 2bd

( Sis, Actually I am having a full portion maths exam tomorrow, since you asked I helped u

Always be : ).